ajax--将JSON从jQuery传递到ASHX
我正在尝试将JSON从jQuery传递到.ASHX文件。 下面的jQuery示例:
$.ajax({
type: "POST",
url: "/test.ashx",
data: "{'file':'dave', 'type':'ward'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
});
如何检索.ASHX文件中的JSON数据? 我有方法:
public void ProcessRequest(HttpContext context)
但我在请求中找不到JSON值。
8个解决方案
56 votes
我知道这太旧了,不过为了记录,我想加5美分
您可以使用此方法读取服务器上的JSON对象
string json = new StreamReader(context.Request.InputStream).ReadToEnd();
Claudio Redi answered -08-10T03:29:11Z
24 votes
以下解决方案为我工作:
客户端:
$.ajax({
type: "POST",
url: "handler.ashx",
data: { firstName: 'stack', lastName: 'overflow' },
// DO NOT SET CONTENT TYPE to json
// contentType: "application/json; charset=utf-8",
// DataType needs to stay, otherwise the response object
// will be treated as a single string
dataType: "json",
success: function (response) {
alert(response.d);
}
});
服务器端.ashx
using System;
using System.Web;
using Newtonsoft.Json;
public class Handler : IHttpHandler
{
public void ProcessRequest(HttpContext context)
{
context.Response.ContentType = "text/plain";
string myName = context.Request.Form["firstName"];
// simulate Microsoft XSS protection
var wrapper = new { d = myName };
context.Response.Write(JsonConvert.SerializeObject(wrapper));
}
public bool IsReusable
{
get
{
return false;
}
}
}
Andre answered -08-10T03:29:39Z
4 votes
如果您将数据发送给服务器DataContractJsonSerializer,则该数据将不会自动转换为JSON数据(请参阅如何构建JSON对象以发送到AJAX WebService?)。 因此,您可以使用context.Request.QueryString["type"]和dataType: "json",而不要使用JSON.stringify或$.toJSON不转换数据。
data: "{'file':'dave', 'type':'ward'}"
(将数据手动转换为JSON),您可以尝试使用
data: {file:'dave', type:'ward'}
并使用DataContractJsonSerializer和context.Request.QueryString["type"]构造在服务器端获取数据。 如果您确实收到这种方式的问题,则可以尝试
data: {file:JSON.stringify(fileValue), type:JSON.stringify(typeValue)}
和使用在服务器端DataContractJsonSerializer。
Oleg answered -08-10T03:30:13Z
2 votes
html
js
(function($) {
$(document).ready(function() {
$('#getReport').click(function(e) {
e.preventDefault();
window.location = 'pathtohandler/reporthandler.ashx?from={0}&to={1}'.f('01.01.0001', '30.30.3030');
});
});
// string format, like C#
String.prototype.format = String.prototype.f = function() {
var str = this;
for (var i = 0; i < arguments.length; i++) {
var reg = new RegExp('\\{' + i + '\\}', 'gm');
str = str.replace(reg, arguments[i]);
}
return str;
};
})(jQuery);
c#
public class ReportHandler : IHttpHandler
{
private const string ReportTemplateName = "report_template.xlsx";
private const string ReportName = "report.xlsx";
public void ProcessRequest(HttpContext context)
{
using (var slDocument = new SLDocument(string.Format("{0}/{1}", HttpContext.Current.Server.MapPath("~"), ReportTemplateName)))
{
context.Response.Clear();
context.Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
context.Response.AddHeader("Content-Disposition", string.Format("attachment; filename={0}", ReportName));
try
{
DateTime from;
if (!DateTime.TryParse(context.Request.Params["from"], out from))
throw new Exception();
DateTime to;
if (!DateTime.TryParse(context.Request.Params["to"], out to))
throw new Exception();
ReportService.FillReport(slDocument, from, to);
slDocument.SaveAs(context.Response.OutputStream);
}
catch (Exception ex)
{
throw new Exception(ex.Message);
}
finally
{
context.Response.End();
}
}
}
public bool IsReusable { get { return false; } }
}
oyaebunterkrah answered -08-10T03:30:28Z
1 votes
这适用于调用Web服务。 不确定.ASHX
$.ajax({
type: "POST",
url: "/test.asmx/SomeWebMethodName",
data: {'file':'dave', 'type':'ward'},
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(msg) {
$('#Status').html(msg.d);
},
error: function(xhr, status, error) {
var err = eval("(" + xhr.responseText + ")");
alert('Error: ' + err.Message);
}
});
[WebMethod]
public string SomeWebMethodName(string file, string type)
{
// do something
return "some status message";
}
Larry Flewwelling answered -08-10T03:30:48Z
0 votes
您必须在Web配置文件中定义处理程序属性,以处理用户定义的扩展请求格式。 用户定义的扩展名是“ .api”
添加动词=“ *” path =“ test.api” type =“ test”将网址:“ / test.ashx”替换为网址:“ / test.api”。
Ashish Sharma answered -08-10T03:31:12Z
-1 votes
如果使用$ .ajax并使用.ashx获取querystring,则不要设置数据类型
$.ajax({
type: "POST",
url: "/test.ashx",
data: {'file':'dave', 'type':'ward'},
**//contentType: "application/json; charset=utf-8",
//dataType: "json"**
});
我得到它的工作!
user411861 answered -08-10T03:31:37Z
-4 votes
尝试System.Web.Script.Serialization.JavaScriptSerializer
随着铸造到字典
Dewfy answered -08-10T03:32:01Z