#include <stdio.h>#include <stdlib.h>#include <string.h>#define N 5double** Link(double a, double b, double c, double d){double** T = NULL;T = (double**)malloc(sizeof(double*)*N);if (NULL == T)return NULL;// 定义一个二维数组，为了给要返回的T 初始化，要不然后面直接赋值会出错double B[N][N] = { 0 };for (int i = 0; i < N; i++){T[i] = (double*)malloc(sizeof(double) * N);if (NULL == T[i])return NULL;for (int j = 0; j < N; j++){T[i][j] = 0;}}// 给二维数组赋值T[0][0] = a;T[0][1] = b; T[0][2] = c;T[0][3] = d;T[1][0] = a;T[1][1] = b;T[1][2] = c;T[1][3] = d;T[2][0] = a;T[2][1] = b;T[2][2] = c;T[2][3] = d;T[3][0] = a;T[3][1] = b;T[3][2] = c;T[3][3] = d;// 返回二维数组return T;}int main(){// 下面的T1 T2两种写法都可以 T2的写法要进行判空double** T1 = NULL; double** T2 = (double**)malloc(sizeof(double*)*N);// 判空if (NULL == T2)return 0;T2 = Link(0, 0.2, 0.2, 0);T1 = Link(0, 0.2, 0.2, 0);for (int i = 0; i < N; i++){for (int j = 0; j < N; j++){printf("%0.1f\t", T2[i][j]);}printf("\n");}system("pause");return 0;}
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