下面先来看看例子：
代码如下
table
id name
1 a
2 b
3 c
4 c
5 b
库结构大概这样，这只是一个简单的例子，实际情况会复杂得多。
比如我想用一条语句查询得到name不重复的所有数据，那就必须使用distinct去掉多余的重复记录。
代码如下
select distinct name from table
得到的结果是:
name
a
b
c
好像达到效果了，可是，我想要得到的是id值呢？改一下查询语句吧:
代码如下
select distinct name, id from table
结果会是:
id name
1 a
2 b
3 c
4 c
5 b
distinct怎么没起作用？作用是起了的，不过他同时作用了两个字段，也就是必须得id与name都相同的才会被排除。。。。。。。
我们再改改查询语句:
select id, distinct name from table
现在将完整语句放出:
代码如下
select *, count(distinct name) from table group by name
结果:
id name count(distinct name)
1 a 1
2 b 1
3 c 1
上面简单但有些地方是不能完成我们的需要的，下面记录了些常用的重复记录操作语句
查询及删除重复记录的方法
(一)
1、查找表中多余的重复记录，重复记录是根据单个字段(peopleId)来判断
代码如下
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
2、删除表中多余的重复记录，重复记录是根据单个字段(peopleId)来判断，只留有rowid最小的记录
代码如下
delete from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
3、查找表中多余的重复记录(多个字段)
代码如下
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、删除表中多余的重复记录(多个字段)，只留有rowid最小的记录
代码如下
delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
5、查找表中多余的重复记录(多个字段)，不包含rowid最小的记录
代码如下
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
