当对象转换成JSON的时候处理时间格式

/// <summary>/// 格式化日期/// </summary>/// <param name="foramt">格式化规则</param>/// <returns></returns>public JsonConverter DateForamt(string foramt){Newtonsoft.Json.Converters.IsoDateTimeConverter dateConverter = new Newtonsoft.Json.Converters.IsoDateTimeConverter(); //格式日期dateConverter.DateTimeFormat = foramt;return dateConverter;}

//调用的时候string json = Newtonsoft.Json.JsonConvert.SerializeObject(T, this.DateForamt("yyyy'-'MM'-'dd HH':'mm':'ss"));

方式二

IsoDateTimeConverter timeFormat = new IsoDateTimeConverter();timeFormat.DateTimeFormat = "yyyy-MM-dd HH:mm:ss";Response.Write(JsonConvert.SerializeObject(bll.GetModelList(strWhere), Newtonsoft.Json.Formatting.Indented, timeFormat));