我有一个python程序,它实现如下线程:class Mythread(threading.Thread):
def __init__(self, name, q):
threading.Thread.__init__(self)
self.name = name
self.q = q
def run(self):
print "Starting %s..." % (self.name)
while True:
## Get data from queue
data = self.q.get()
## do_some_processing with data ###
process_data(data)
## Mark Queue item as done
self.q.task_done()
print "Exiting %s..." % (self.name)
def call_threaded_program():
##Setup the threads. Define threads,queue,locks
threads = []
q = Queue.Queue()
thread_count = n #some number
data_list = [] #some data list containing data
##Create Threads
for thread_id in range(1, thread_count+1):
thread_name = "Thread-" + str(thread_id)
thread = Mythread(thread_name,q)
thread.daemon = True
thread.start()
##Fill data in Queue
for data_item in data_list:
q.put(data_item)
try:
##Wait for queue to be exhausted and then exit main program
q.join()
except (keyboardInterrupt, SystemExit) as e:
print "Interrupt Issued. Exiting Program with error state: %s"%(str(e))
exit(1)
调用_threaded_program()是从另一个程序调用的。
我让代码在正常情况下工作。但是,如果其中一个线程中发生错误/异常,则程序将被阻塞(因为队列连接是无限阻塞的)。我能退出这个程序的唯一方法就是关闭终端本身。
当线程退出时,终止此程序的最佳方法是什么?有没有一个干净的(实际上我会采取任何方式)方法来做这件事?我知道这个问题已经问了很多次了,但我仍然找不到令人信服的答案。我非常感谢你的帮助。
编辑:
我尝试删除队列上的连接,并使用了Is there any way to kill a Thread in Python?中建议的全局退出标志
然而,现在的行为是如此奇怪,我无法理解是怎么回事。import threading
import Queue
import time
exit_flag = False
class Mythread (threading.Thread):
def __init__(self,name,q):
threading.Thread.__init__(self)
self.name = name
self.q = q
def run(self):
try:
# Start Thread
print "Starting %s...."%(self.name)
# Do Some Processing
while not exit_flag:
data = self.q.get()
print "%s processing %s"%(self.name,str(data))
self.q.task_done()
# Exit thread
print "Exiting %s..."%(self.name)
except Exception as e:
print "Exiting %s due to Error: %s"%(self.name,str(e))
def main():
global exit_flag
##Setup the threads. Define threads,queue,locks
threads = []
q = Queue.Queue()
thread_count = 20
data_list = range(1,50)
##Create Threads
for thread_id in range(1,thread_count+1):
thread_name = "Thread-" + str(thread_id)
thread = Mythread(thread_name,q)
thread.daemon = True
threads.append(thread)
thread.start()
##Fill data in Queue
for data_item in data_list:
q.put(data_item)
try:
##Wait for queue to be exhausted and then exit main program
while not q.empty():
pass
# Stop the threads
exit_flag = True
# Wait for threads to finish
print "Waiting for threads to finish..."
while threading.activeCount() > 1:
print "Active Threads:",threading.activeCount()
time.sleep(1)
pass
print "Finished Successfully"
except (KeyboardInterrupt, SystemExit) as e:
print "Interrupt Issued. Exiting Program with error state: %s"%(str(e))
if __name__ == '__main__':
main()
程序输出如下:#Threads get started correctly
#The output also is getting processed but then towards the end, All i see are
Active Threads: 16
Active Threads: 16
Active Threads: 16...
然后程序将挂起或继续打印活动线程。但是,由于exit标志设置为True,因此线程的run方法不会被执行。所以我不知道这些线索是如何保持的,也不知道发生了什么。
编辑:
我发现了问题。在上面的代码中,线程的get方法被阻塞,因此无法退出。相反,使用带有超时的get方法完成了这个任务。我有下面修改的run方法的代码def run(self):
try:
#Start Thread
printing "Starting %s..."%(self.name)
#Do Some processing
while not exit_flag:
try:
data = self.q.get(True,self.timeout)
print "%s processing %s"%(self.name,str(data))
self.q.task_done()
except:
print "Queue Empty or Timeout Occurred. Try Again for %s"%(self.name)
# Exit thread
print "Exiting %s..."%(self.name)
except Exception as e:
print "Exiting %s due to Error: %s"%(self.name,str(e))