满意答案
csmes
.08.27
采纳率：41%等级：13
已帮助：8466人
你先看看吧，思路大概就是这样，不懂的问我。
#include
#include
#include
using namespace std;
struct point
{
float x;
float y;
};
void translation(point*pt, float xp,float yp,int num)//num代表点的个数
{
for(int i=0;i
{
(pt+i)->x+=xp;
(pt+i)->y+=yp;
}
}
void scale(point *pt,float xs,float ys,int num)
{
for(int i=0;i
{
(pt+i)->x*=xs;
(pt+i)->y*=ys;
}
}
void rotation(point *pt,float angle,int num)
{
int a[2][2];
angle=angle/180*3.141592657;
a[0][0]=cos(angle);
a[0][1]=-sin(angle);
a[1][0]=sin(angle);
a[1][1]=cos(angle);
point* temp;
for(int i=0;i
{
temp->x=(pt+i)->x;
temp->y=(pt+i)->y;
(pt+i)->x=temp->x*a[0][0]+a[0][1]*temp->y;
(pt+i)->y*=temp->x*a[1][0]+a[1][1]*temp->y;
}
}
int main()
{
int i=0,N,mode,angle,xp,yp,xk,yk,num;
cout<
scanf("%d",&N);
num=N;
point pt[10];
while(N--)
{
printf("please input points(x,y):\n");
scanf("%f%f",&pt[i].x,&pt[i].y);
i++;
}
printf("please input motions\n");
printf("0 stand for translation:\n");
printf("1 stand for scale:\n");
printf("2 stand for rotation:\n");
scanf("%d",&mode);
switch(mode)
{
case 0:
printf("please input the translation in x and y direction respectivly:\n");
cin>>xp>>yp;
translation(pt, xp,yp,num);
break;
case 1:
printf("please input the scale in x and y direction respectivly:\n");
scanf("%f%f",&xk,&yk);
scale(pt, xk,yk,num);
break;
case 2:
printf("please input the angle:\n");
scanf("%f",&angle);
rotation(pt, angle,num);
break;
}
printf("after translatiton or scale or rotation:\n");
for(int i=0;i
printf("%f %f\n",pt[i].x,pt[i].y);
}
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