问题补充:
已知|ab-2|与|b-1|互为相反数,试求代数式1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+)(b+)的值
答案:
|ab-2|=|b-1|=0
a=2,b=1
1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+)(b+)
=1-1/=/
时间:2021-10-23 18:29:35
已知|ab-2|与|b-1|互为相反数,试求代数式1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+)(b+)的值
|ab-2|=|b-1|=0
a=2,b=1
1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+…+1/(a+)(b+)
=1-1/=/
已知AB互为相反数 MN互为倒数 C的绝对值为2 求代数式a+b/+mn-1/4c的
2019-11-01