问题补充:
求定积分:[(e的sinx次方)乘以cosx]dx,上限是2分之pai,下限是0?$(acontent)
答案:
∫[0,π/2] e^(sinx ) cosxdx= ∫[0,π/2] e^(sinx ) dsinx= e^(sinx ) | [0,π/2] =e-1
======以下答案可供参考======
供参考答案1:
∫(0,π/2)[(e的sinx次方)乘以cosx]dx
=∫(0,π/2)[(e的sinx次方)dsinx
=e^(sinx)|(0,π/2)
=e-1
时间:2020-08-09 18:35:52
求定积分:[(e的sinx次方)乘以cosx]dx,上限是2分之pai,下限是0?$(acontent)
∫[0,π/2] e^(sinx ) cosxdx= ∫[0,π/2] e^(sinx ) dsinx= e^(sinx ) | [0,π/2] =e-1
======以下答案可供参考======
供参考答案1:
∫(0,π/2)[(e的sinx次方)乘以cosx]dx
=∫(0,π/2)[(e的sinx次方)dsinx
=e^(sinx)|(0,π/2)
=e-1
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